23x=11x^2=2

Solution for 23x=11x^2=2 equation:

23x=11x^2=2

We move all terms to the left:

23x-(11x^2)=0

determiningTheFunctionDomain
-11x^2+23x=0

a = -11; b = 23; c = 0;
Δ = b2-4ac
Δ = 232-4·(-11)·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-23}{2*-11}=\frac{-46}{-22}
=2+1/11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+23}{2*-11}=\frac{0}{-22}
=0
$